Concrete Beam HW HELP!

[smithyjj199421]

points) using ultimate strength design method determine the flexural steel required for an

interior concrete beam to span 26’-0”. Use #8 bars for the flexural steel. Solve for the number of

bars. The un-factored live load is 1300 plf. The un-factored dead load is 1100 plf and includes

the self-weight of the beam. The beam is 18” wide and 22” deep.

Reference Module 6

Lessons 6.1 and 6.2.

Fc'=4,000 psi

Fy=40,000 psi

Flexural Steel #8 Bars

_________

Load factors (live load, dead Load)

_________

wusd(load per plf)

_________

Maximum moment USD LB-FT

_________

Mmax USD theoretical LB-FT

_________

Mmax USD theoretical LB-INCHES

_________

b

_________

Minimum cover per code

_________

Effective depth d

_________

a Used

_________

As required per bending calculations

_________

As required per minimum steel ratio

_________

Final As required for flexural steel (from all calculations or minimum reinforcing ratio considerations)

_________

Required number of #8 bars

_________

 

[leggo PE]

It looks like you laid out the steps to solve this problem pretty much for yourself, so I'm not sure what help I could provide besides giving you the exact equations. However, I feel like you probably have access to the equations to calculate, for instance, load combinations, d, a, A_s-required, A_s-min, and then figure out the amount of #8 bars based on the area of a single #8 bar and the amount of A_s you need.

Good luck!

 

[MA_PE]

That looks like the problem statement period.  I think the op wants us to fill in the blanks.  What code does the problem want?  ACI 318?