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Help Support Engineer Boards:

  1. S

    motion sensors this project have completely describe the instrumentation of sensor and its connection, check this out it will be really help full. connect detail of arduino and ESP32 connections.
  2. S

    Motion in a magnetic field

    flaming right hand rule show the direction of currrent in the megnatic field
  3. S

    AutoTransformer Question

    It means actual winding power handling capacity is only 1015 KVA but this autotransformer can handle 5000 KVA means auto transformer can handle 5 times more power and 5 times smaller than a conventional 2 winding transformer
  4. S

    Electromangetic Filed fluction

    An electromagnet can be used for moving scrap steel from one place to another. In a scrapyard, a crane has a large iron disc that is not a permanent magnet. The crane operator lowers the electromagnet into a pile of scrap steel and then switches on the electricity.
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    Green energy analysis - Research

    go search on google scholar it contain nuemours reseacrh paper. it can help you
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    Average Age to take FE/PE/SE

    FE at 23 and PE at 26
  7. S

    Potentiometer replacement. Any thought? this will help you in doing replacement of the joystick using reed switch. this project discussion will help you understand counter going to the digital pot.
  8. S

    Percent Voltage Drop

    [email protected] - 480: @ is equal to theta Vd-Value * sqrt(3) 480 [email protected] - 277/480 Vd-Value 277
  9. S

    Generator internal voltage

    ye the answer should be :Vi = Vt + Id*Xd = 1+ 0.97*1.1j = 1.46 pu So, the voltage is 1.46 * 250 kV = 365.6 kV there can be mistake in solution manual.
  10. S

    Problem 530 (NCEES)

    we can use MVA Method, 40MVA in series with 25 MVA (1MVA/.04) and 40 X 25 / (40+25) = 15.38 MVA we find out that Fault is on the 480v bus 15.38MVA/(sqrt(3) * 480e-6MV) = 18,500A
  11. S

    Code question

    clearly mention that 277V is single phase connected across L-N.
  12. S

    home made electrical components

    To create a wirewound resistor, one piece of wire would have to serve as the path for the electrical current to flow from one end of the resistor to the other. To create a resistor with a small resistance (or Ohm) value, use a thicker, shorter wire as the path between the two electrical leads.