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Yes I did MDM. Oooph! Started off shaky. Moved to ones I could decipher. Then guessed a couple too. Second guessing myself on some questions but I will just wait and see. Sent from my SM-N950U1 using Tapatalk

I actually tested in Edmond too. Fingers crossed. I'm trying to mentor some college students on FE and doing some otrher things to pass time. The wait can be nerve-wrecking but I will find positive things to do to improve my community while I wait.

And don't wear cologne.

Shigley is on standby for me.

Similar to mine, though I have all my solved problems in a question bank folder and tabbed by each topic.

I totally agree. I believe this week should be about making sure you are grounded in concepts and problem identification, in case they switch something up on me.

Curious about what is in the 2011 MSM. Got it on Amazon. I guess presentation doesn't matter as long as the content is there.

Thank you so much. i got halfway and got stuck.

Please do you guys mind sharing your calculation? Thanks.

Is this question set up right? Deflections at the ends will be zero. Maybe I'm missing something?

Maybe the calculator Sent from my SM-N950U1 using Tapatalk

You are overthinking the problem. Everything you need is in the question. I don't know if you have access to control chart equations and factors. The formula needed are in the attached document.

Failure by principal stresses will be for brittle materials which wasn't specified. A similar problem in NCEES practice exam specified the failure criterion to use.

Your solution seems correct to me. I used exactly the same approach and got the same answer. I wont overthink it especially when the fatigue stress concentration is not provided and the shaft is not a stepped shaft. Why don't you email the authors. It is definitely a typo. The question should be...

Correct. Thanks Slay the PE

Hello, please can you share the 2011 MDM practice exams with me: [email protected].  Thanks 

You are right. I had it wrong

I believe option C is also correct. P2 is creating a torsional stress/twisting effect on the section a-a, and torsional stress is minimum on the external fibers and maximum at the center.

No, it's a wrong solution. The author already corrected it in the errata. it should be 2 for Nw. The answer is 33.33 rpm which is not part of the answers

Thank you so much. It makes sense.