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Well, the Oct 2018 MDM test is done.  I have absolutely no clue on how I did.  I kind of feel like I got beat up a little bit.  There were a lot of problems that I think I did well with (esp. in afternoon), and there were several that I just didn't understand very well (both morning &amp...

Yeah, this one is waayyy different than the others I've seen posted around here.  The MDM test makers beat me up a little bit today.  Ouch!

Word.

Thanks man...I'm probably gonna need all the help I can get!  Sitting in this room is letting doubts creep in and I'm losing confidence by the hour!

I still have no idea what i'm gonna eat for lunch.  I'm guessing we have an hour, right?

I hear you man.  I'm going to hit a few problems from the last few weeks in the review and then call it good.  After that, I'm gonna turn on some movies and flip through my reference material and tab important charts/tables that I haven't already.

Well, I'm at the hotel and for my references I've brought along: MERM Dr. Tom Binders Engineering Unit Conversions It doesn't sound like a lot, but they sure are heavy to lug around.

I haven't even thought this far ahead.  I may be screwed!

Ahhh, that's a time saver for sure.  I tried to get familiar with the IC method in the MERM, but it didn't really make sense to me so I moved on pretty quickly.  Maybe if i have some extra time, i'll give it another shot.

Wow, a one-liner for a crank/slider problem.  Nice!  What reference did you find that in?

I noticed that the MERM has a pretty decent sized Fe-C phase diagram.  I might have to make a copy of that also and put it into the materials binder.  Then i need to figure out how i'm going to tote all these binders into the room.  I guess i'll just roll them in with a carry-on suitcase.      

Looks like we have about 14 days and a wake-up.  I'm starting to get a little bit nervous.  My hotel is reserved, and exam authorization is in.  I'm doing some early review and then it will be getting things together and organized.  What's on everybody's "to-do" list?

There it is!  Nice work!

Hey Ski, yeah...it's just an easy way to remember that perpendicular slopes are inverses.  Formally, the negative inverse.  But in our case, we don't care about signage, as that is taken into account with the component equations of the vector. 

Not a bad idea.  It's been a while since I've done any IC problems.  Does anyone have a solution using the IC method?

Here is a copy of the crank/slider solution if anyone is interested.  I definitely wouldn't consider this to be a 6 minute problem.  I had to do a fair amount of angle finding and then break up the vector equation into x/y components, being careful to keep things straight.  Hopefully somebody...

Ski, im not sure if this property has an official name.  Maybe "reciprocal slope" or something.  But if you have a line defined by y=2x and you need to find the line perpindicular to it, it woud be the recipricol and of course negative slope, y=-x/2. Now for the easy way to remember or think...

I'm getting 2.0 for the SF on the buckling problem assuming it's within the Euler range.  The safety factor I used was Pcrit/P.

Hey Ski, remember that the direction of that torsional shear is 90 degrees from the line you are using for your length ratios (5 & 6).  Since it is 90 deg from that line, the actual leg ratios of the stress are now reversed from that of the "r" that you used.  In other words, the rise...

Now that I'm thinking about it, this might be helpful to people to avoid unit issues with lbm and lbf: