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I got nervous last week LOL. Now its gone, looking forward to the exam date! I want to get over this already. LOL 3 months no life.

I got mine from Ebay.

Exactly what I was about to say. Also for those that sent me a pm. Sorry guys, don't want to get in any kind of trouble. It is as cfm03 said.

Oh yes, did the conversion, its the same. The one I downloaded should suffice. Thanks! 

I was thinking of buying one on amazon this metric steam table by Keenan and Keyes. Its $82.5.  But was thinking about if its going to be worth it just for the purpose of using in the exam?  I have a Metric steam tables but the Sat. Temperatures only go up to 373celcius, Sat. Pressure only up...

I agree only for some particular pressures, and only if you are comfortable using the most 11x17, unless you want waste time flipping that huge paper and folding it back after solving.  In some cases mollier chart are faster, but not all the time. Specially if pressures are over 2500psi, I...

The h2 you get from super heated steam tables is the h2' (actual) as the problem given you the actual conditions.  Now calculating the theoretical 100% efficiency. You use S1=S2 Then theoretically, the condition of state 2 should be in saturated pressure tables. You would go to saturation...

Answer should be C

I think not, temperature are different just have to equate both v1/(kgcRT1)^1/2=(v2/kgcRT2)^1/2 You get  v2

I believe what we going to actually see in the exam is just same weight as NCEES practice test, its not going to go too much way beyond that, some questions might appear more difficult but I think that's just because the problems are foreign.  I'm almost done with my first pass on SlayPE, it...

Thanks for sharing Mike! I did a check on my work. For example, if I follow my approach and started at say getting velocity based on 3000GPM the available head of both pumps should be around 60.8ft Then I calculated velocity based on 3000gpm 1ft diameter and multiply the value by 2 for two...

Thank you! Once Im done with these I'll definitely check it out.

Hello guys, Just needed some advice if my approach and solution are correct?  I solved this problem but did a different solution path, my solution was quicker than whats presented in the solution page, I did get the correct answer before looking at the solution. So I was thinking maybe I just...

I hear you, and evrytime I answered problems correctly within 6 minutes I was like yes!!! Felt pretty good lol. Im at the pm section now of SlayPE, so far there are like 30% of the problems I encountered took me morethan 6min to solve and some about 5 questions I couldnt figure out a solution...

I see! NICE! Thanks for explaining that! 

Why did you use v 13.3ft^3/lbm to calculate mass of air from point 1? Shouldn't you use 13.95ft^3/lbm to get the initial amount of dry air? If you calculate the initial mass of air from v=13.3ft^3/lbm how then can you dehumidify it? Also how then did you find that point with v=13.3 if you are...

Ok

OMG lol we did all the same calculation, so the W2 is rounded off to 0.013? From 0.010258? This is the only way I see that line hitting close to 60F.  I used 0.0102 for W2 since rules of rounding off, you round off odd numbers next to 5's. I did get 0.16 earlier doing same steps, close answer...

EDIT! Sorry was 0.12!!! I took a better look at the graph. And that's where it should be. So A? While cooling and dehumidifying, following the saturation line until you reach W2 = 0.0102 calculated from condensate mass. Tdbout is 58F that is where condensation stops. 

awesome! thanks!