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Also, keep in mind that the voltage ratio may not always cancel, say, if the actual voltage on the primary side of the transformer is not equal to the transformer's voltage ratio.

Sorry, I thought you were asking about the transformer. Yes, for generator, kV_base=22kV. Here is the breakdown of the process: When you select a base MVA, this will be same for all components. So, both transformer and the generator has same base MVA. On the other hand, base kV will not be same...

Also, to answer your question, base voltage at transformer secondary is 230 kV. kV_b=230kV. This is equal to the transformer secondary voltage. kV_new=230kV and kV_old=230kV, so the ratio is 1. Read the article from the above link and everything will be clear.

You should read this: Per Unit Example - How To, Tips, Tricks, and What to Watch Out for on the Electrical Pe Exam - Electrical PE Review

Power Ncees 52

Power System Analysis and Design by Glover, Sarma, and Overbye Electrical Machinery and Power System Fundamentals by Chapman Electrical Machines, Drives and Power Systems by Wildi Eng Pro Guide's Power PE Textbook Eng Pro Guide's Power PE References Exam Cram for the Power PE Exam Vol 1-4 by...

277V is single phase connected across L-N. The question clearly states that it is a 3-phase load, so you use 480V. Looks like you're struggling with basics. If you have any reference book on basic electrical, you should go through it.

The exam is now CBT. You are not allowed to bring any references. The only thing you'll be taking in the exam center is your calculator. You'll be provided a reference handbook, and all the required code books. Here is a demo

There are three motors, and the highest is 10 hp. The code says to sum 125% of FLC of the highest rated motor (10 hp) with FLC of other motors. So, 125% of FLC of 10 hp motor is 1.25*14=17.5A. Add this to the FLC of other motors. 17.5+11+7.6=36.1A. On a side note, I think you should enroll in...

They are parallel conductors, so the impedance will be halved. For e.g. if you have two resistors in parallel (with equal resistance), 1/Req=(1/R)+(1/R), which gives Req=R/2. See pic below. Not exactly similar to the question, but you get the idea.

Because 74.75A is the maximum, which means you can not exceed this value. So, you select the next smaller standard size, which is 70A.

Before adding the capacitor, all the current needs to be supplied by the source (including reactive current). When you add capacitor on the load side of the motor, reactive current drawn by the motor is provided by the capacitor. So, the total current flowing in the motor circuit up to the...

Enroll in Zach Stone's course at electricalpereview.com. Another option is engproguides.com. I wasn't enrolled in engproguide's course, so I don't know how it is, but his reference book and practice exams are good. Edit: Sorry I thought you were asking for Power exam.

How familiar are you with NEC? If you're someone who has barely used it before, buy Complex Imaginary's code drill book to get familiar with chapters. After that, buy engproguide's References Exam and work on the problem multiple times. Conductor sizing, overcurrent protection, and grounding are...