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My take on this is somewhere around 4 months to 8 months minimum. I myself studied for over a year, but that was because my exam was pushed back twice. I started studying around November 2019, and I was originally supposed to take the exam on April 2020. But that got pushed back due to CoViD...

Read the question carefully - it is asking for the maximum trip current setting (also sometimes called the ultimate trip setting), which is not necessarily the same as the actual device size to be used.

This is pretty informative. Never thought that specifically about synching 3-phase generators with different phase windings/connections. Thanks for the FYI!

I was trying to find what the next steps are after finding out I passed the PE exam. Dothracki, thanks for your input! I guess now we just play the waiting game... at least we passed!!!

OOF, you're right. Careless mistake on my part! Maybe later when I have some free time, I'll retry this problem.

I posted on your website, but unfortunately I can't seem to upload the screenshots of my work. I got 2.2 amps on my attempt. I attached screenshots of my attempt on this problem...

Congrats to you as well for passing!!!

Well, I finally got my results today and I am very happy to say that I PASSED!!! I seriously have to thank this forum and also @Zach Stone P.E. (Electrical PE Review) , @justin-hawaii (Eng Pro Guides), and @Cram For The PE for all of their resources and help throughout studying for this exam...

Since the system and transformer have different KVA ratings, did you use the Zpu new = Zpu old * (Sbase new / Sbase old) * (Vbase old /Vbase new)^2 formula to convert one of the base impedances to the correct impedance value per the new system base?

For 110: the given load is only a 1-phase load, connected between 2 phases. You do not need to use the square root of 3 for a single phase load. For 132: you are asked to find the fault current resulting from a 3-phase fault. The given voltage is a line-to-line voltage, and the division by...

Hey guys, Responding to the questions about the single-line-to-ground fault from the Electrical PE Review exam. See the attached circuit diagram analysis. I should note the following: For a single line to ground fault with Phase A faulted, Van = 0 at the location of the fault. Ib = Ic = 0...

Congrats!!!

Best of luck. Hope you pass. But also one thing I told myself is not to take it too hard if I don't pass on my first shot. There will be other chances I can take later down the road to try again. I think this is something you should also keep in mind. Either way, I really hope you pass. Best...

Well, I just took it for the first time today. Without saying too much, even with all the preparation I did, I'm not sure whether or not I passed.

Well, I finally took the Power exam today. Without saying too much, I'm not sure if I passed. If not, I'll see if I can take a second shot at it later...

Hey guys, I have a very silly question out of preparation paranoia... A (state) driver's license is sufficient for them to confirm your identity, right? Very silly question, I know. But I just want to make sure that my driver's license will be sufficient for them to confirm my identity.

Hey, I'm circling back to this because I'm still a bit lost. So let's say for example: a 3-ph, 13000 V / 240 V transformer. If you were asked for BOTH primary and secondary protection for such a transformer, you have to use both tables even for just this one transformer? So the Table for Over...

I'm pretty sure I know which question you're talking about: The one about charging line current, you're asked if it's directly proportional to voltage, line length, capacitance, and radius (I think). I chg = Vs LN / Xc = Vs LN / (1/wC) = w * C * Vs LN So the charging current is directly...

I think when Zach says proportional, he means it can be either directly multiplied or divided between one number and another number. Basically, proportional means: a = n * b I guess there is a difference between directly or inversely related, and directly or inversely proportional. @Zach...

Here is how I understand it. For induction motors, I agree with you. Induction motors need slip (difference in speed between synch speed ns and rotor speed n) to generate torque for the load. The more a rotor's speed n decreases away from synch speed ns, the more slip and thus the more torque...