Recent content by lost4ever P.E.

Thanks for help. I will contact.

What should my exemption references fill in the blank after "I am legally exempt from licensure because" ......... ? Does anyone else have any advice on how to help reference fill out the form when they are likely not familiar with the terminology in the form. Thanks

@LyceeFruit PE I checked on " next steps" and its taking me to the link below and attached form. https://www.bpelsg.ca.gov/applicants/appinstpe.shtml Unfortunately, I don't work under PE and I do not have references. I have no idea whom I have to consult for help.

hi ryjames, I have passed PE power in California and I would like to apply for license. What documentation I have to prepare to get license? Thanks

@akyip, thanks. I read twice and confuse. Now its clear.

I thought the selected device would be 100 Amps, but the answer is 103.5 Amps. Any help would be appreciate.

@RedRaider2020, thanks now its clear.

@RedRaider2020, how did you get Z = 0.04p.u?

Yes I used the similar formula Transformer : 0.04 (1000/1000)*(0.48/0.48)^2 = 0.04 p.u System: 0.04 (1000/40000)(12.47/0.48)^2 = 0.67 p.u

Hi to all, Can anyone help me with the impedance calculation. base kva = 1000 base kV = 0.48 I got X p.u for transformer is 0.04 and for system is 0.67 I don't know what I am doing wrong?

Thanks all appreciate your support. It is clear to me now.

@DarkLegion Can you show me your attempt? I tried again and getting similar results.

Anyone can help me please Question 69 (Electrical PE Preview Technical Guide) Z0+Z1+Z2 = 10 + 7j ohm I0 = 646.6A<-35.8 SLG fault My approach : For SLG fault I0=I1=I2 Ia = I0+I1+I2=3*646.6<-35.8 = 1939.8<-35.8 Vph = 1939.8<-35.8 * (10+7j) =23.898<-0.1 kV Vline =...

Anyone had experienced that one or more questions from April would be repeated in October?

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