Three Phase Polar Math question - Power Exam Sub Forum - Engineer Boards
Jump to content
Engineer Boards
Sign in to follow this  
Spickett

Three Phase Polar Math question

Recommended Posts

image.png.323b735731a0dfd38ab239e06545eb1b.png

 

I can't for the life of me figure out how to get 7480<-21.2. It's a step in an example circuit analysis problem from School of PE.

 

Polar math is kicking my butt at the moment. Cant anyone help me understand how to work this.

 

-Steve  

Share this post


Link to post
Share on other sites

When I enter what you posted into my calculator, I get 784.7<42.9, so something is amiss.  Would you mind posting the entire problem?

Share this post


Link to post
Share on other sites

At least I'm not crazy. I got that 784.7<42.9 as well. Here's the whole example. My only issue is that they did the example this was as well as with another method and came up to the same 13KV

 

image.thumb.png.6e4df46f9531da354ece3a8f78dd0d95.png

Edited by Spickett

Share this post


Link to post
Share on other sites

Check your units.  For VaA you're multiplying amps times your impedence, which gives you volts.  VAN is in kV, so when you add the two in your previous question, you need to multiply  VAN x 10^3 so it's in volts before you add it to VaN.

Edited by MEtoEE
  • Like 2

Share this post


Link to post
Share on other sites

Thank you so much.

 

That was breaking me.

Share this post


Link to post
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
Sign in to follow this  

×
×
  • Create New...