Graffeo: Ind. Motor - Power Exam Sub Forum - Engineer Boards
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# Graffeo: Ind. Motor

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Is there any one who can help me with this one?

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Work through chapter 15 of Wildi's book. He goes through the equivalent circuit step by step.

Much more thorough than what can be explained on a message board.

If you don't have the book - get it and read it! I read it cover to cover and was glad I did. I picked up an copy on eBay for ~\$20.

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Sorry for the late response. Thank you  @ellen3720 for your kind suggestion. I do have Wildi book. I just want to know if Graffeo Pmax came from same logic as mentioned in Wildi. Yes definitely i will follow Wildi.

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I tried to solve Graffeo Ex38 by Wilid method but i got different answers than one in the Graffeo.

I think i am missing something with my calculation.

Please let me know who have done this problem with Wildi method.

For those who don't know the question:

"A 120V, 6OHz, 6 pole, delta connected, three phase induction motor has the following characteristics. At standstill: Z stator = 0.2+j 0.25 ohm; Z rotor = 0.3+j 0.35 ohm. Find Pmax. The slip at which Pmax occurs and the Torque N- m at that point."

Book ans: Pmax= 16.88 KW; Slip=0.278; Torque=186.05 N-m

My ans: Pmax=8.687 KW; Slip=0.476; Torque=69 N-m

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On 3/1/2019 at 3:16 PM, Sdhabik said:

I tried to solve Graffeo Ex38 by Wilid method but i got different answers than one in the Graffeo.

I think i am missing something with my calculation.

Please let me know who have done this problem with Wildi method.

For those who don't know the question:

"A 120V, 6OHz, 6 pole, delta connected, three phase induction motor has the following characteristics. At standstill: Z stator = 0.2+j 0.25 ohm; Z rotor = 0.3+j 0.35 ohm. Find Pmax. The slip at which Pmax occurs and the Torque N- m at that point."

Book ans: Pmax= 16.88 KW; Slip=0.278; Torque=186.05 N-m

My ans: Pmax=8.687 KW; Slip=0.476; Torque=69 N-m

Still waiting for someone to response on this.

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On 3/5/2019 at 7:45 PM, Sdhabik said:

Still waiting for someone to response on this.

What formula are you using for slip?

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On 7/10/2019 at 11:02 AM, Wow! said:

What formula are you using for slip?

From Wildi equation 15.8:

For max power/torque; R2/S=IZ1I

where R2= 0.3

Z1= r1+jx = 0.2+j(0.25+0.35) = 0.2+j0.6 = 0.632<71.6 deg

Therfore, S=R2/IZ1I = 0.3/0.632 = 0.475

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Page 103 if Geaffeo explains that max power occurs when the load resistance is the same as stand still impedance.

for this condition, slip = r_rotor divided by

(r_rotor + Ze)

Ze is the square root of re ^2 + xe^2

where re is r_rotor plus r_ stator

and xe is x_rotor plus x_ stator

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So max slip equals

.3/(.3+.78)=.278

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Finally torque is pmax/w_m

pmax calculated above is 16875 watts

w_m= (1-s_p) *w_s

s_p is defined as slip for pmax, 0.278

w_s = 4pi f/ p

this is the same as 120f/p multiplied by 2pi/ 60 to convert to rad per sec

w_s=4pi* 60/6 poles = 125.6

w_m= (1-.278)* 125.6= 90.6 rad per second

torque=16875/90.6 = 186.258Nm

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can you try with wildi method as well plz.

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