Need help with CBT practice problem #28 - Chemical Exam - Engineer Boards
Jump to content
Engineer Boards
 photo CHPE_AnimatedWebBanner_650x1202_zps5704d467.gif
Sign in to follow this  
TrustmeImanengineer

Need help with CBT practice problem #28

Recommended Posts

hi all,

Due to copyright concerns and lack of legal knowledge, I cannot post the problem itself here.

I just do not understand why in the solution the enthalpy of the heating jacket is being used instead of the enthalpy at saturated steam pressure of 0 psia. The question is obviously asking for the feed rate to the evaporator, not the heating jacket. 

And I have a feeling this confusion is from my lack of understanding of an evaporator, and I am confusing myself with the feeds?

Share this post


Link to post
Share on other sites
 photo CHPE_AnimatedWebBanner_650x1202_zps5704d467.gif

Let's simplify the problem:

1. Saturated Water @ P1 --> EVAPORATOR --> Saturated Steam @ P1           |           Q = m (water) x delta H (vaporization @ P1)

2. Saturated Steam @ P2 --> Heating Jacket of EVAPORATOR --> Saturated Water @ P2         |           Q = m (steam) x delta H (condensation @ P2)

The convective heat transfer between sat. steam (@ P2) and inlet water (@ P1) (Q=UA x delta T) must be equal to the heat of condensation of steam in the jacket AND heat of vaporization of water in the EVAPORATOR. Depending on what the question asks for, either steam or water, you may use the first or second equation. 

 

Edited by GasPro

Share this post


Link to post
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
Sign in to follow this  

×
×
  • Create New...