CERM Practice Problems - Intersection Design

CERM Practice Problems - Intersection Design

I am working on problem located on page 73-3, problem number 4 of the CERM Practice Problems book. It is an intersection design problem. When looking at the solution the effective green is described as " Since the lost time includes the amber time, the effective green is the actual green time."

My question is shouldn't this be g = G + Y + AR - tl? I would think lost time due to start up from green (usually 2 secs) should be the minimum tl.

Any insight would be appreciated.

Thank you

See page 10-13 of the HCM. I didn't realize this till now, but that figure comes in real handy. It makes it easier to understand the relationship between the various signal cycles. I believe you're correct in which the lost time is separate from the Y (yellow+all red) they shouldn't be grouping it together but the lost time needs to be subtracted for the G+Y to equal g......