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rmsg

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About rmsg

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    Electrical

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  1. The output at AB is not going to be 3 phase, it is going to be either one of the single phase, so yes then the peak to peak of that one of the single phase will be 125Vrms * root(2) = 177V.
  2. rmsg

    To everyone taking the test on Friday

    Thanks. Yes, I also have the same printout of ANSI in my binder. I am too expecting (may be one) question where I have to use this ANSI sheet. Do you remember how hard were Switchgear Protection and Coordination questions ? This time a lot of focus is on that topic (13 questions)..
  3. Although I am also appearing for the first time so cannot be an expert on commenting, but I would advice do not overthink it too much. The chances are that around 50 percent of exam will be very simple : basic one on one transformation to input parameters into the formula and get the result (that would include all code question). Rest 50 percent would be a challenge, where one has to think beyond the box and sort out a twist or so in the problem. If you have gone through the course material (what ever you are preparing from, be it Eng Pro guide or Graffeo or School of PE etc.) I would suggest that from now on to the exam day, just read all your material and read all the solved problems see how it is solved rather than trying to solve by yourself now. Make notes of which problem is solved how and take those notes with you in the exam. Trust me any handwritten notes you will make now will help you recall where in the material you have to find the solution. All the best. Keep motivated. Don't panic and loose heart. Cheers..
  4. That is a lot of material my friend to carry to the test. I thought I was taking too many books/binders and should reduce it. I think we all may overwhelm ourselves in the exam if we take too many books. Just a thought. I do have made my own binders with a lot of notes on each one of the nine topics and a index sheet with page numbers so that I don't get too much lost in the exam trying to remember oh my ! where have I seen this particular question/topic. Good Luck !
  5. Hi All, To my understanding of Power Systems 3 Phase Circuits, I found something which does not make sense to me. Please see Solution 30 of Eng Pro Guide Test.In my opinion, Justin Kauwale should make some corrections here. See enclosed PDF, In the question above it is assumed 0.85 lagging power factor, yet in the solution below it is stated 0.85 leading (current leads the voltage) Then later below it is said : cos (theta) = 0.85 -> theta = -31.8 degree (negative for lagging) Actually in my opinion, cos (theta) is power factor and therefore cos inverse (theta) here is power factor angle which should be positive instead of calling it negative for assumed lagging system. Yet I see that in the expression of Vp after 2 lines, I think he got it right there by saying current = 1.0<-31.8 degree. In actuality current angle is negative (opposite sign of power factor angle). so I believe in the end by taking current = 1.0<-31.8 degree he got the final answer right, but there are mistakes/discrepancies in the explanation above I believe some corrections needs to be made here. Please comment if anyone thinks other wise. Solution 30 - Transformers - Correction.pdf
  6. rmsg

    What is allowed in exam

    Oh yes, I remember it now, had to go through that for FE exam also.
  7. rmsg

    Exam authorization notice

    I got it yesterday in email. Actually log on to your NCEES account and you will see a link to authorization document
  8. rmsg

    What is allowed in exam

    what is Prometric Polygraph ?
  9. Thanks Zach. sure I will if needed. Regards,
  10. Hi Zach, I had joined your course for a couple of month and then left, I think I should have continued. But I must say of all the course materials out there, yours is the best. I am hoping all your course notes and solved problems which I am taking in the exam will help me. Thanks..
  11. rmsg

    Complex Power Current Conjugate S=VI*

    Conjugate comes into play because normally current's phase angle is opposite sign of actual power factor angle. Power factor angle is normally same angle as impedance angle Power is also written as P = (V x V)/Z but since the other formula where V and I are taken, we have to consider the conjugate of current angle not the actual current angle So in essence just remember that the conjugate I angle is same as Power Angle or Impedance angle Z, which should be used for Power
  12. rmsg

    NCEES Question 530

    Thanks Zach, and I agree one can check the work also.
  13. rmsg

    What is allowed in exam

    I have similar question, I am giving exam first time as I don't have prior experience. I am planning to take around 15 odd books/binders which would fit in at least 2 suitcase. I will prioritize the strongly needed books in one suitcase and the other seldom used in other suitcase. From past exam takers, please let me know if we have to take all the books at one time inside or we can come back to collect later or do they allow a suitcase as it is (packed) near my seat so I can open the suitcase if I need less prior books. Secondly if we don't have choice and have to carry all the books in one shot, then the table/seat they allow (is it big enough) to accommodate the books or we can put some of the less important books on floor beside us.
  14. rmsg

    NCEES Question 530

    that does makes some sense, so the total impedance is the impedance of system (with 40MVA = 0.025p.u.) + impedance of Transformer which is 4% impedance so z transf (p.u.) = 4% = 0.04 so total z(p.u.) = 0.04 + 0.025 = 0.065 right ? if my interpretation is correct, than many thanks. I think I got it. Cheers..
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