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monty01

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About monty01

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    Mechanical
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    EIT
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    TI
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    Mechanical

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  1. monty01

    Machine Design & Materials Oct 2018

    I noticed that the MERM has a pretty decent sized Fe-C phase diagram. I might have to make a copy of that also and put it into the materials binder. Then i need to figure out how i'm going to tote all these binders into the room. I guess i'll just roll them in with a carry-on suitcase.
  2. monty01

    Machine Design & Materials Oct 2018

    Looks like we have about 14 days and a wake-up. I'm starting to get a little bit nervous. My hotel is reserved, and exam authorization is in. I'm doing some early review and then it will be getting things together and organized. What's on everybody's "to-do" list?
  3. monty01

    MD&M practice problem of the week

    There it is! Nice work!
  4. monty01

    Eccentric Loading of Bolted Joint

    Hey Ski, yeah...it's just an easy way to remember that perpendicular slopes are inverses. Formally, the negative inverse. But in our case, we don't care about signage, as that is taken into account with the component equations of the vector.
  5. monty01

    MD&M practice problem of the week

    Not a bad idea. It's been a while since I've done any IC problems. Does anyone have a solution using the IC method?
  6. monty01

    MD&M practice problem of the week

    Here is a copy of the crank/slider solution if anyone is interested. I definitely wouldn't consider this to be a 6 minute problem. I had to do a fair amount of angle finding and then break up the vector equation into x/y components, being careful to keep things straight. Hopefully somebody else has a quicker solution. I'd have to say this one is a "C" and I'd only go back to it if I had some time toward the end.
  7. monty01

    Eccentric Loading of Bolted Joint

    Ski, im not sure if this property has an official name. Maybe "reciprocal slope" or something. But if you have a line defined by y=2x and you need to find the line perpindicular to it, it woud be the recipricol and of course negative slope, y=-x/2. Now for the easy way to remember or think about it. What about the x and y axes? Y has an infinite rise, X has an infinite run.
  8. monty01

    MD&M practice problem of the week

    I'm getting 2.0 for the SF on the buckling problem assuming it's within the Euler range. The safety factor I used was Pcrit/P.
  9. monty01

    Eccentric Loading of Bolted Joint

    Hey Ski, remember that the direction of that torsional shear is 90 degrees from the line you are using for your length ratios (5 & 6). Since it is 90 deg from that line, the actual leg ratios of the stress are now reversed from that of the "r" that you used. In other words, the rise becomes the run and vice versa for a line normal to the "reference" line. In order to check this, draw a 3/4/5 triangle on engineering paper, then draw a line normal to that hypotenuse. Compare the slope of your new line to the original hypotenuse. To summarize, the actual stress vector for torsional shear has a rise of 5 and a run of 6 (opposite from the line from center of bolt group to bolt): Fx = F(5/7.81) Fy = F(6/7.81)
  10. monty01

    MD&M practice problem of the week

    Now that I'm thinking about it, this might be helpful to people to avoid unit issues with lbm and lbf:
  11. monty01

    MD&M practice problem of the week

    I think i have OCD when it comes to writing. If my radical lines aren't straight, it throws me off! My straight edges are gonna be burning up on test day!
  12. monty01

    MD&M practice problem of the week

    I'm with Dr. Tom when it comes to lbm and lbf. I use slugs instead, which is where the W/g came from.
  13. monty01

    MD&M practice problem of the week

    Wow, now we have to show our work!?!?! Hard chargers around here! Give me a couple of minutes and i'll see if i can get the solution uploaded. Support Vibration.pdf
  14. monty01

    MD&M practice problem of the week

    I get (B) for this one, with a ratio |X/Y| = 1.65. Zeta is zero (no damping).
  15. monty01

    MD&M practice problem of the week

    Haha...support & isolation is actually next weeks lesson. I'll have to take a stab at this later today.
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