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rg1

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About rg1

  • Rank
    Principal in Charge
  • Birthday January 1

Previous Fields

  • Engineering Field
    Electrical Power
  • License
    PE
  • Discipline
    Electrical

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    Male
  • Location
    Omnipresent

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  1. The PE licence is not US based. It is based on state. Rules differs from state to state. California state rules, I do not know if they have changed now are "If you have not worked in a country where ppl are PE, experience certification from non PE guys will be valid." Please visit the state Board website for details. Hope this answers your first level of question. Feel free to ask specific questions in understanding the rules of a board. Outsource you can email the board directly. regards
  2. Someone gave me this advise. I found useful. However I did all chapters and all chapter end questions. It was helpful. Chapter 1---show you how to use the per unitChapter 2 ---If you don't remember the basics of KVL, KCL etc.Chapter 3, 4, 5....i barely touch it....is DC generators and motors...so no need to worry about those.Chapter 7-12 ---needs to be studied....discussed power and transformers.---this is like 45% of the exam.Chapter 13-15--needs to be studied....it discussed motors....when i study for the PE i concentrate on motors not generators....generators is the same thing but reverse.Chapter 17---needs to be studied... synchronous motor.Chapter 21--needs to be studied....power electronics....from power electronics you just need to know if the input wave look like this how would look the output wave.Chapter 24- gives you an understanding of how the power is generated....i read it... interesting chapter.Chapter 25 & 26- Transmission and distribution.....these are important chapters that needs to be studied....in fact there was a question in the real exam that i answer the question from one of those chapters.Chapter 30 - Harmonics you at least need to know what cause it....what is a 2nd order 3rd order...etc. I wouldn't skip this one.
  3. I think, Hand written in pencil are not allowed anywhere, because that will be understood as if you have done it in the exam, which is prohibited. Hand written in pencil and then Xeroxed should not be an issue.
  4. Perfect! There can be 4 combinations. The boundary limits are, do not exceed the rated current of the coils, rated voltage of the coil, see for addition or subtraction (dot convention) of voltage depending on buck/boost. The transformation ratios of currents and voltages (make sure directions are correct) still holds good between the two coils as was there when conventionally connected. The input VA is always equal to output VA. The last two sentences are very important. With above items in mind one should be able to do all AT questions. If it does not help, let me understand your specific gap in the understanding; I will help you fill that gap.
  5. It is my pleasure. If any one is having any doubt or if you are not getting some question, you can PM me, Whenever I visit the forum, I will try to answer your queries.
  6. The dot notation for transformer is- If in one dot the current goes in the coil, in the other dot the current will come out of the coil. The voltage sign on dots will be same as positive. So in left coil, the current goes in and in the right coil current comes out. The left coil consumes power and the right coil delivers power!!!!
  7. Please follow the steps (in circles) in the given diagram to reach the answer. Step 4 is interesting. I would like you guys understand the stuff. If you do not follow how I got a particular answer in a particular step, just let me know. I will explain that step.
  8. Hints 1. Total voltage across both paths is same. 2. Voltage across transformers comes from transformation ratio give. 3. Current in one path in given, the current in other path will be such that (1) above is satisfied.
  9. The problem is a lagging load, but how does it matter here. You have been given a load and Voltage. Rest is maths. Yes if the solution has taken Vbn with +120 degrees, it is wrong as per convention. Conventionally phase sequence is ABC. May be because the question asks only magnitude part which remains unaffected by talking any two phases. Taking Van <0 and Vbn<-120 is more correct. I give one more spin to the solution for better appreciation. Find out the impedance of the load from KVA and V and then find the currents in what ever phases you connect this impedance. Add them to find the neutral current.
  10. I have suggestion. Start with one beer, with increment of one, each passing day. The anxiety will increase each passing day and so will the dose. I managed it in a different way. I went to attend an Indian marriage, the party goes on for more than a week ......... Party till you get the result......................
  11. Till you give up it is not a failure, it is only work in process and I have yet to see someone who did not give up and failed. I am sure you must be feeling yourself better prepared and doing better every time than what you did last time. Now when you extrapolate the graph there is point of time on x axis, when one breaks the barrier on y axis. May be you are reaching that level this time. Best wishes. Now coming to the worst situation..... Since you have already put in lot of efforts, continuing it, is a better option then taking a break and restarting it. My experience has been that except code questions and some formula reference, the references are not much of use. I took 2 Codes (NESC, NEC), Wildi book and my own notes. I referred Wildi book only once. Rest three were more useful. For me getting answers by refering a book takes more time than 6 minutes. I prefer to do it without much of reference. I consider reference is only a help or hint, the question does not appear in the exam as it is from the references. Anyways, stay positive, my best wishes are there with you and would like to see you passing this time.
  12. One question which comes to my mind is what is the protection angle of shield wire. perhaps it is 30 degrees. Please verify data before use.
  13. Generally synchronous motors are the loads which feed the fault. This is because they have energy of their inertia of rotation. This energy is dissipated as electrical energy into the fault, as the motor starts working as generator once the terminal voltage of motor reduces due to fault. If you go deep into the subject, inductive and capacitive energy stored in the power system in various such loads also contributes to the fault. Having stated this fact, if I am right in my prediction, I do not expect such concepts mixed with fault current questions in PE exams. Most of the fault current questions are asked from steady state point of view and what we are talking about ( synchronous motors, inductive and capacitive loads can only feed the fault till they exhaust of their energy which is for a small initial duration). And the Load bus is a passive element and will never contribute any energy to the fault.
  14. The question 21 is wrong. You simply transform the current across transformers to get Generator current. There is no role of base voltage and base power there. Rather they could have specified actual Generator Voltage to ask for Generator current. You can do it directly by Power formula Power= V1*I1=V2*I2 =V3*I3. You have been given Load current (Region 3) so you can directly jump to region1---- The power supplied by generator is equal to consumed by load.
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