# NCEES Sample Problem #507 - Construction PM

Started by
Lucky1
, Dec 05 2011 02:35 AM

8 replies to this topic

### #5

Posted 06 December 2011 - 03:20 AM

Problem #515 is the one in question.

Apparently it's in the way the problem is worded if the delay time is added into the cycle time or subtracted from 60 minutes when calculating cycles/hr.

I guess I can see the confusion, but these problems always work with a cycle time with no delay. The delay is taken out in the hour portion. This allows for things like worker breaks, etc. The trick part of Problem #515 is recognizing the weight limit in how much the truck can haul per cycle.

### #9

Posted 05 April 2012 - 04:18 PM

Yeah, the way I approached it was we are looking for Cyles per hour. Without a 5-min delay we have 17min/60min.cycle/1hr = 0.28 hrs/cycle. The reciprocal gives 3.52 cycles/hr. OK.

Now, if we subtract 5 min from the demoninator we have 17 min/55min.cycle/1hr = 0.31 hrs/cyle. The reciprocal gives 3.23 cycles/hr < 3.52 (above). Therefore I've now convinced myself the 5 minute delay slows production. The frist time I worked this problem it bothered me subtracting 5 out of the denominator...seemed like a contradiction. But if you check the units it makes sense.... Good problem.

Now, if we subtract 5 min from the demoninator we have 17 min/55min.cycle/1hr = 0.31 hrs/cyle. The reciprocal gives 3.23 cycles/hr < 3.52 (above). Therefore I've now convinced myself the 5 minute delay slows production. The frist time I worked this problem it bothered me subtracting 5 out of the denominator...seemed like a contradiction. But if you check the units it makes sense.... Good problem.

**Edited by Jayman_10x, 05 April 2012 - 04:18 PM.**

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