I posted the problem below under the forum Construction section and have gotten no replies... wanted to see if anyone in Structures can help.

I am looking for an end restraint coefficient C=2.1 referenced in the answer as coming from NDS but can't find where.

Thanks in advance for any help!

Lindeburg Practice Problems book

Problem 45.3 (11th ed)

A 4in x 4 in (nominal size) timber post is used to support a sign. The post's modulus of elasticity is 1.5x10^6 lbf/in^2. One end of the post is embedded in a deep concrete base. The other end supports a sign 9 ft above the ground. Neglect torsion and wind effects. What is the Euler load sign weight that will cause failure by buckling?

a- 2700 lbf

b- 3700lbf

c- 4000lbf

d- 5500lbf

Answer:

1) I = bh^3/12= (3.5)(3.5^3)/12= 12.51 in^4 (finished lumber size)

2) k = (I/A) ^ 1/2

k= (12.51/(3.5"x 3.5"))^1/2= 1.01 inches

3) The end restraint coefficient is C= 2.1 (NDS) <--- this line is quoted directly from Lindeburg's problem book. Does anyone know where to find this C=2.1 figure in NDS? (I obviously don't know how to use this reference) Any body have any pointers???

4) The slenderness ratio is:

L'/k= CL/k= (2.1)(9'x12)/1.01 = 224.6

There is note here: L/k is well above 100. (Note that most timber codes limit L/k to 50, so this would not be a permitted application).

5) Fe= (pi)^2 E I/ (L^2) = [(pi^2) (1.5 x 10^6 lbf/in^2) ( 12.51 in^4)] / [((2.1)(9'x12"))^2] = 3673 lbf

Answer is therefore b.

Anybody? End-restraint coefficient C = 2.1 (from NDS). This is a timber post.

I glanced to through the tables and a couple spots in NDS, but I had no luck.

# Wood problem needing NDS

Started by
Construction PE
, Oct 20 2011 06:07 PM

1 reply to this topic

#### 0 user(s) are reading this topic

0 members, 0 guests, 0 anonymous users