Environmental Solved Problems - HELP
#1
Posted 16 September 2011 - 01:40 AM
PLEASE?!
#2
Posted 16 September 2011 - 03:02 AM
In other words, don't get too hung up on the occasional problem in Schneiter that you can't solve using the EnvERM. Try to find the source, but don't waste too much time or worry if you can't. Tab the page so you can reference that equation during the exam, and move on.
#3
Posted 16 September 2011 - 03:06 PM
#4
Posted 16 September 2011 - 05:51 PM
#5
Posted 16 September 2011 - 06:52 PM
#6
Posted 17 September 2011 - 04:46 AM
#7
Posted 24 September 2011 - 06:43 PM
Where can I find the the 7.7mg/L DO in water @ Temp=22C and elevation correction factor of 0.88 that they refer to in the solution? Initially I thought it would be App 22D.
Thanks
#8
Posted 24 September 2011 - 10:12 PM
thanks
#9
Posted 03 October 2011 - 06:55 PM
Where can I find the the 7.7mg/L DO in water @ Temp=22C and elevation correction factor of 0.88 that they refer to in the solution? Initially I thought it would be App 22D.
Thanks
#10
Posted 06 October 2011 - 08:23 PM
Where can I find the the 7.7mg/L DO in water @ Temp=22C and elevation correction factor of 0.88 that they refer to in the solution? Initially I thought it would be App 22D.
Thanks
The saturation of DO in water (in mg/L) at standard atmospheric conditions varies with temperature, for other pressures, the solubilities vary approximately in proportion to the ratios of these pressures to the standard pressures (Pactual/Pstandard).
So...According to App22.D @ 22C the DO content is 8.83 mg/L. I don't have the problem, but I am assuming that the pressure correction factor is given or derived from a simple ratio or the equation given at the bottom of App22.D...Therefore, the actual [DO] in the water would be Csactual = Csstandard (Pcorrection)
Csactual = 8.83 *(0.88)
= 7.77 mg/L DO
#11
Posted 06 October 2011 - 11:27 PM
Where can I find the the 7.7mg/L DO in water @ Temp=22C and elevation correction factor of 0.88 that they refer to in the solution? Initially I thought it would be App 22D.
Thanks
The saturation of DO in water (in mg/L) at standard atmospheric conditions varies with temperature, for other pressures, the solubilities vary approximately in proportion to the ratios of these pressures to the standard pressures (Pactual/Pstandard).
So...According to App22.D @ 22C the DO content is 8.83 mg/L. I don't have the problem, but I am assuming that the pressure correction factor is given or derived from a simple ratio or the equation given at the bottom of App22.D...Therefore, the actual [DO] in the water would be Csactual = Csstandard (Pcorrection)
Csactual = 8.83 *(0.88)
= 7.77 mg/L DO
That's it! Thanks! Turns out I misread table 36.1 and it works just as well but now I know why. EngineerBoards.com is awesome!
#12
Posted 07 October 2011 - 02:33 AM
Occasionally, I earn my keep.
Good luck on the exam.
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