# NCEES 2008 problem #501

3 replies to this topic

### #1 PEin2010

PEin2010

Project Engineer

• Senior Member
• 86 posts
• Gender:Female
• Location:California
• Discipline:Civil

Posted 27 October 2010 - 09:24 PM

Why is the answer 63 kips (ASD) / 94 (LRFD) and not 125 kips (ASD) / 187 (LRFD)???

When to use the maximum uniform load given by the table and when to use the Vn/ factor of safety (the value given at the bottom of the column on pg. 3-74 / AISC manual)???

Thank you!

### #2 MTeeden

MTeeden

Intern

• Members
• 19 posts
• Discipline:Civil

Posted 27 October 2010 - 10:15 PM

QUOTE (PEin2010 @ Oct 27 2010, 05:24 PM) <{POST_SNAPBACK}>
Why is the answer 63 kips (ASD) / 94 (LRFD) and not 125 kips (ASD) / 187 (LRFD)???

When to use the maximum uniform load given by the table and when to use the Vn/ factor of safety (the value given at the bottom of the column on pg. 3-74 / AISC manual)???

Thank you!

Don't have the question in front of me, but I'm pretty sure that shear failure governs in that case. Max shear is 94 kips

### #3 dastuff

dastuff

Principal in Charge

• Veteran
• 389 posts
• Gender:Male
• Location:Los Angeles
• Discipline:Structural

Posted 28 October 2010 - 04:55 PM

I bet this ties into your other question and you should be dividing by two

### #4 wow

wow

NC Professional Engineer

• Senior Member
• 35 posts
• Gender:Male
• Discipline:Civil

Posted 26 October 2011 - 01:54 PM

If the load were fixed at the center, then you would multiply the allowable shear load by 2. But this is a MOVING load, so if the load were placed nearest to one of the ends, then shear governs (62.5 k) as the allowable shear force would equal the applied load.

#### 0 user(s) are reading this topic

0 members, 0 guests, 0 anonymous users

=