Effective net area - steel member
Posted 26 September 2010 - 09:00 PM
As I understand it, Effective net area, An = Ag (gross area) - effective hole diameter (bolt dia. + 1/16 + 1/16)*member thickness + s^2/4*g
I'm not sure when to use the the s^2/4*g term. Also the spacing for the bolts is given.
Any help is appreciated. Thanks!
Posted 27 September 2010 - 01:43 PM
Net area (An) is the gross area (Ag) minus the area of the holes with a 1/16" increase in diameter, or diameter of bolt + 1/8".
Effective net area takes into account the shear lag factor (U) described in AISC section D3.3.
Ae = An*U
Posted 27 September 2010 - 05:15 PM
Posted 27 September 2010 - 05:30 PM
so if there is a single row of bolts, for a double angle having a gross area of say 5.71 in^2, the net area (An)= 5.71 (gross area) - 2 (since it's a double angle)*effective hole diameter (bolt dia. + 1/16 + 1/16)*member thickness. Is that correct?
And to get the effective net area, it will be An*U. I read the relevant section, but not quite sure how U is calculated. I think U should be equal to 1.0 for my example, but somehow I don't get the right answer.
Posted 27 September 2010 - 09:25 PM
Look at Table D3.1 Case 2. This is the situation that have if you have. Look at the commentary figure C-D3.2 on pg 16.1-251 (AISC 13th edition).
L is the length from first bolt to the last bolt, or (number of bolts - 1)*(typical bolt spacing).
Xbar is found in the section properties tables.
Posted 27 September 2010 - 10:04 PM
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