robertplant22
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The question goes as follows:
A 208V wye-connected, ungrounded sytem suffers a ground at pahse A. Waht is most nearly the line voltage at phase B?
The answer to the question is 208*SQRT(3) = 360V
however I tought that for a wye connected transformer:
VB= VBN - VCN
The explanation in the answer indicates that because phase A is grounded VB becomes
VB= VAN - VBN which results in a magnitude of 208*SQRT(3).
Can someone elavorate on this? Also if phase A is grounded would it not make sense to say that the voltage VAN = 0 ?
Thanks in advance for any input.
A 208V wye-connected, ungrounded sytem suffers a ground at pahse A. Waht is most nearly the line voltage at phase B?
The answer to the question is 208*SQRT(3) = 360V
however I tought that for a wye connected transformer:
VB= VBN - VCN
The explanation in the answer indicates that because phase A is grounded VB becomes
VB= VAN - VBN which results in a magnitude of 208*SQRT(3).
Can someone elavorate on this? Also if phase A is grounded would it not make sense to say that the voltage VAN = 0 ?
Thanks in advance for any input.