Two watt meter method and power factor

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Chaser

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Given two wattmeters ( w1 and w2) reading from a 3 phase circuit, how do you identify if a load is capacitive or inductive? please advise.

 
you'd have to be given more information than just that

 
I believe that its capacitive (sending VA), then you have P < 0 and it's inductive (receiving VA), P > 0. Hopefully this helps

 
HotFudge said:
I believe that its capacitive (sending VA), then you have P < 0 and it's inductive (receiving VA), P > 0. Hopefully this helps
Click to expand...
real power (P) cannot be negative. only reactive power (Q) can

 
Chaser said:
Given two wattmeters ( w1 and w2) reading from a 3 phase circuit, how do you identify if a load is capacitive or inductive? please advise.
Click to expand...
In two watt meter method

(Sings of W1, W2 preserved)

W1+W2= Sqrt3 V(line) I(line) cos(phi) =Real power consumed by Load=P

and W1-W2= V(line) I(line) Sin(phi)= 1/sqrt3 of Reactive power.=Q/sqrt3

The sign of Q will decide whether the pf is lag or lead.

 

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